<p>Hey guys i have this bonus question for school could any one help plz ??</p>

Question

<p>Hey guys i have this bonus question for school could any one help plz ??</p>
<p>we are taking lessons about Electriacal energy and current &#160;, so the solution steps must be using the formulas related to these lessons :)</p>
<p>Q) A pair of oppositely charged parallel plates are separated by( 5.33x10-3 meters) .A potentail diffrence of 600.0 V exists between the plates .</p>
<p>A) hat is the magnitude of the electrical field strenght in the region that is located between the plates?</p>
<p>B) what is the magnitude of the force on an elctron that is in the region between plates at a point that is exactly ( 2.90x10-3 meters) from the positive plates ?</p>
<p>C) the electron is moved to the negative plate from an initial position &#160;( 2.90x10-3 meters) from the positive plate. What is the change in the Electrical potential energy due to the movment of this electron ?</p>
<p>Plz try helping me even if u just know how to solve one of them &#160;:)</p>
<p>btw the answers are provided but the teacher wants to see the steps :D</p>
<p>answers as following :</p>
<p>A) 1.13x10^5 V/m</p>
<p>B) 1.81x10^-14 N</p>
<p>c) 4.39x10^-17 J</p>
<p>thanks</p>

Explanation / Answer

A pair of oppositely charged parallel plates are separated by( 5.33x10-3 meters) .A potentail diffrence of 600.0 V exists between the plates (A) Distance, d = 5.33 x 10^-3 m Potential difference, V = 600.0 V Electric field, E = V/d                         = 600 / ( 5.33 x 10^-3)                         = 1.13 x 10^5 V/m (B) Force, F = E q                = 1.13 x 10^5 * 1.6 x 10^-19                = 1.81 x 10^-14 N (C) Displacement, d = ( 5.33 - 2.90 ) x 10^-3                          = 2.43 x 10^-3 m Change in electric potential energy = Work done                                                      = F * d                                                      = 1.81 x 10^-14 * 2.43 x 10^-3                                                      = 4.39 x 10^-17 J

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