please show all step clearly, and explain No work or explanation? No units? No b

Question

please show all step clearly, and explain

No work or explanation? No units? No boxed answer? No credit! Calculation Question A golfer strikes the ball off of the tee (x,y,z = ,,). The center of the hole is located a distance of 165m north(*x> and 68m west(+y) of the tee. The upper edge of the hole is 9m below(-z) the height of the tee. If the ball is launched from the tee at a 4 degree angle (with respect to the horizontal), what minimum launch velocity is required to make the ball land in the hole? Express the launch velocity in (x.y.z) component form.

Explanation / Answer

Without using the "range on an inclined plane" formula, which is rather complex, a very accurate estimate can easily be made The horizontal distance to the hole is D = (165^2 + 68^2)^1/2 = 178.5 m When the ball again falls to the horizontal level let X be distance from the hole (also it will be travelling at 40 deg from horizontal) So X = 9 / tan 40 to a very close approximation X = 10.7 m So the ball travelled 178.5 - 10.7 = 167.8 m before again reaching horizontal Now use the "range" formula R = v^2 * sin (2 theta) / g v = [167.8 * 9.8 / (167.8 * sin 80)]^1/2 = 40.9 m/s

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