(a) to the right or (b) to the left The figure shows a 23-cm long metal rod pull
ID: 2006562 • Letter: #
Question
(a) to the right
or
(b) to the left
The figure shows a 23-cm long metal rod pulled along two frictionless, conducting rails at a constant speed of 3.3 m/s. The rails have negligible resistance, but the rod has a resistance of 0.65 Ohm. Part A - What is the current induced in the rod? Express your answer using two significant figures. I = A Part B - What is the magnitude of the force is required to keep the rod moving at a constant speed? Express your answer using two significant figures. F = N Part C And what is the direction of this force? (a) to the right or (b) to the leftExplanation / Answer
Given: Length of the metal rod = L = 23 cm = 0.23 m Metal rod pulled across the conducting rails with constant speed = v = 3.3 m/s Resistence of the rod = R = 0.65 Magnetic field applied = B = 1.4 T Part: A ) It is known by the formula for induced e.m.f in the rod is induced e.m.f is ( e) = B L v = (1.4)(0.23)(3.3) = 1.0626 volts thus, induced current in the loop is Iinduced = einduced / R = (1.0626)/ (0.65) Iinduced = 1.63476 A Part: B ) The amont of force needed to moving the rod at a constant speed is : F = B Iinduced L = (1.4)()1.63476(0.23) F = 0.52639 N Part: C ) Direction of this force is LEFT Length of the metal rod = L = 23 cm = 0.23 m Metal rod pulled across the conducting rails with constant speed = v = 3.3 m/s Resistence of the rod = R = 0.65 Magnetic field applied = B = 1.4 T Part: A ) It is known by the formula for induced e.m.f in the rod is induced e.m.f is ( e) = B L v = (1.4)(0.23)(3.3) = 1.0626 volts thus, induced current in the loop is Iinduced = einduced / R = (1.0626)/ (0.65) Iinduced = 1.63476 A Part: B ) The amont of force needed to moving the rod at a constant speed is : F = B Iinduced L = (1.4)()1.63476(0.23) F = 0.52639 N Part: C ) Direction of this force is LEFTRelated Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.