(a) vector A (b) vector B (c) vector C (d) vector D (e) none, because the field
ID: 2027523 • Letter: #
Question
(a) vector A
(b) vector B
(c) vector C
(d) vector D
(e) none, because the field is zero at point P
(a) 2F
(b) F
(c) 1/2F
(d) zero
(e) none of these
(3) Two charges are located along the x-axis as shown. Where could the electric field be zero, if at all?
(a) nowhere
(b) in region I to the left of Q
(c) in region III to the right of -2Q
(d) in region II, but closer to -2Q than Q
(e) in region II, but closer to Q than -2Q
(3) Two charges are located along the x - axis as shown. Where could the electric field be zero, if at all? (a) nowhere (b) in region I to the left of Q (c) in region III to the right of - 2Q (d) in region II, but closer to - 2Q than Q (e) in region II, but closer to Q than - 2Q (2) A charge +q is placed at the origin of a coordinate system, and a charge of +Q is located at +a on the x - axis. The force on +Q is found to be F. A third charge - q is now placed at +2a on the x - axis and the force on +Q is now (a) 2F (b) F (c) 1/2F (d) zero (e) none of these (1) Two charges +Q and - Q are located as shown. Point P is on the perpendicular bisector of the line joining the charges. Which indicates the direction of the electric field there. (a) vector A (b) vector B (c) vector C (d) vector D (e) none, because the field is zero at point PExplanation / Answer
C. The y components cancel. A. 2F since they both want it to go to the right. b. In region 1.
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