Coil 1 has an inductance of .035 H and 100 turns. Coil 2 has an inductance of .0
ID: 2008414 • Letter: C
Question
Coil 1 has an inductance of .035 H and 100 turns. Coil 2 has an inductance of .055 H and 185 turns. The coils are rigidly positioned with respect to each other, their mutual inductance is .004 H. A .008 A current in coil 1 is changing at a rate of 7.0 A/s.1) What flux links coil1? (Not 1.73*10^-7 Wb or 2.8*10^-6 Wb) 2) What is the magnitude of the self-induced emf that appears in coil 1?
.240 V
3)What flux links coil 2? (Not 1.73*10^-7 Wb or 2.8*10^-6 Wb) 4) What is the magnitude of the mutually induced emf that appears in coil 2? .0280 V Coil 1 has an inductance of .035 H and 100 turns. Coil 2 has an inductance of .055 H and 185 turns. The coils are rigidly positioned with respect to each other, their mutual inductance is .004 H. A .008 A current in coil 1 is changing at a rate of 7.0 A/s.
1) What flux links coil1? (Not 1.73*10^-7 Wb or 2.8*10^-6 Wb) 2) What is the magnitude of the self-induced emf that appears in coil 1?
.240 V
3)What flux links coil 2? (Not 1.73*10^-7 Wb or 2.8*10^-6 Wb) 4) What is the magnitude of the mutually induced emf that appears in coil 2? .0280 V
Explanation / Answer
for coil 1 : inductance L1 = 0.035 H number of turns N1 = 100 current i1 = 0.008 A current rate (di/dt)1 = 7 A/s current i1 = 0.008 A current rate (di/dt)1 = 7 A/s for coil 2 : inductance L2 = 0.055 H number of turns N2 = 185 mutual inductance M = 0.004 H .......................................................... 1) magnetic flux in coil 1 is 1 = L1i1/N1 = (0.035)(0.008) / (100) = 2.8*10-6Wb = 2.8 Wb = 2.8 Wb .......................................................... 2) emf = L1(di/dt)1 = (0.035)(7) = 0.245 V ......................................................... 3) magnetic flux in coil 2 is 2 = Mi1/N2 = (0.004)(0.008)/(185) = 1.73*10-7 Wb ˜ 173 nWb ˜ 173 nWb ........................................................... 4) mutual inductance emf = M(di/dt) = (0.004)(7) = 0.028 VRelated Questions
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