Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

a uniform magnetic field of 0.8 T. The wire makes an angle of 37degree with the

ID: 2009123 • Letter: A

Question

a uniform magnetic field of 0.8 T. The wire makes an angle of 37degree with the direction of B. What is the magnitude of the force on the wire? A long wire parallel to the x axis carries a current of 14 A in the direction of increasing x. There is a uniform magnetic field of magnitude 8000 G in the positive y direction. Find the force per unit length on the wire. Section 21-2 Torques on Magnets and Current Loops A small magnet is placed in a magnetic field of 0.15 T. The maximum torque experienced by the magnet is 0.20 Nm What is the magnetic moment of the magnet? If the length of the magnet is 4.0 cm, what is its pole strength A small circular coil of 20 turns of wire lies in a uniform magnetic field of 0.5 T such that the normal to the plane of the coil makes an angle of 60degree with the direction of B. The radius of the coil is 4 cm, and it carries a current of 3.0 A. What is the magnitude of the magnetic moment of the coil? What torque is exerted on the coil? A rectangular, 50-turn coil has sides 6.0 and 8.0 cm long

Explanation / Answer

Number of turns in the circular coil is N = 20 magnetic field B = 0.5 T Radius of the coil is r = 4.0 cm current in the coil is i = 3.0 A a ) magnetic moment of the coil is   M = N IA                                                            = 20 * 3.0 A * (4.0*10^-2m)^2                                                            = 0.301 A m^2 b ) torque exerted in the coil is = N i A B                                                    = 20 * 3.0A *  (4.0*10^-2m)^2 * 0.5 T                                                    = 0.15 N m