A capacitor is placed across a battery and allowed to charge completely. The bat

Question

A capacitor is placed across a battery and allowed to charge completely. The battery is then disconnected and the plates of the capacitor are then moved apart (d increases). State what happened to each of the quantities below (increases, decreases, or stays the same) as the plates were pulled apart.

Capacitance, C

Voltage across the capacitor, Vc

Charge on the plates, Q

Energy stored in the capacitor, U






A capacitor is placed across a battery and allowed to charge completely. The battery remains connected and the plates of the capacitor are then moved apart (d increases). State what happened to each of the quantities below (increases, decreases, or stays the same) as the plates were pulled apart.

Capacitance, C

Voltage across the capacitor, Vc

Charge on the plates, Q

Energy stored in the capacitor, U

Explanation / Answer

Capacitance of parallel plate capacitor is given by                           C = 0A/d ..........(1)                                                                      where                                                 A = Area of the plates of the capacitors                                                  d = Distance between the plates. If distance between the plates is increases. i.) Capacitance of the capacitor is decreases. Because from equation (1) it is clear that distance and capacitance are inversly proportional to each other. ii) Voltage across the capacitor V = q/C Hence as the capacitance decreases, Voltage across the capacitor Increases. iii) As charge and voltage are in directly proportional to each other,So charge on the plates increases. iv) Energy stored in capacitor U = 1/2 CV2 Energy is also increases. iii) As charge and voltage are in directly proportional to each other,So charge on the plates increases. iv) Energy stored in capacitor U = 1/2 CV2 Energy is also increases.

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