A capacitor is placed across a battery and allowed to charge completely. The bat
ID: 2010973 • Letter: A
Question
A capacitor is placed across a battery and allowed to charge completely. The battery is then disconnected and the plates of the capacitor are then moved apart (d increases). State what happened to each of the quantities below (increases, decreases, or stays the same) as the plates were pulled apart and what would happen to the same quantities if the battery wasn't disconnected as the plates are pulled apart. Explain your reasoning.Capacitance, C
Voltage across the capacitor, Vc
Charge on the plates, Q
Energy stored in the capacitor, U
Explanation / Answer
"(1) capacitance of parallel plate capacitor C = e0A/d ..........(1) where A is the area of the plates of the capacitors d isthe distance between the plates. if distance between the plates is increases. i.) Capacitance of the capacitor is decreases . because distance and capacitance are in reciprocal from equation 1 . ii) V = q/C hence voltage and capacitance are inversly proportional if C decreaes V is increases iii) from second part charge and voltage are in directly proportional hence charge between the plates increases. iiii) Energy stored in capacitro U = 1/2 CV2 Energy is also increases."
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