The sun emits electromagnetic waves with a power of 4.0*10 26 W. Part A - Determ
ID: 2012029 • Letter: T
Question
The sun emits electromagnetic waves with a power of 4.0*1026 W.
Part A -
Determine the intensity of electromagnetic waves from the sun just outside the atmosphere of Venus. Refer to the ff astronomical data:
Mean distance
from sun(m) period(yrs) Mass(kg) Mean Radius(m)
Venus 1.08 x 1011 .615 4.88 x 1024 6.06 x 106
Mars 2.28 x 1011 1.88 6.42 x 1023 3.37 x 106
Saturn 1.43 x 1012 29.5 5.68 x 1026 5.85 x 107
Express your answer using two significant figures.I = ________W/m2
Part B -Determine the intensity of electromagnetic waves from the sun just outside the atmosphere of Mars.
Express your answer using two significant figures.
I = __________W/m2
Part C -
Determine the intensity of electromagnetic waves from the sun just outside the atmosphere of Saturn.
Express your answer using two significant figures.
I = _________ W/m2
Explanation / Answer
The power of the electromagnetic waves emited by Sun is P = 4.0*10^26 W If the distance of the Venus from Sun r = 1.08*10^11 m Then the intensity of the radiation I = P/4r^2 = (4.0*10^26 W) / 4(1.08*10^11 m)^2 = 2730.38 W/m^2 If the distance of the Mars from Sun r = 2.28*10^11 m Then the intensity of the radiation I = P/4r^2 = (4.0*10^26 W) / 4(2.28*10^11 m)^2 = 612.63 W/m^2 If the distance of the Saturn from Sun r = 1.43*10^12 m Then the intensity of the radiation I = P/4r^2 = (4.0*10^26 W) / 4(1.43*10^12 m)^2 = 15.57 W/m^2 Then the intensity of the radiation I = P/4r^2 = (4.0*10^26 W) / 4(2.28*10^11 m)^2 = 612.63 W/m^2 If the distance of the Saturn from Sun r = 1.43*10^12 m Then the intensity of the radiation I = P/4r^2 = (4.0*10^26 W) / 4(1.43*10^12 m)^2 = 15.57 W/m^2 Then the intensity of the radiation I = P/4r^2 = (4.0*10^26 W) / 4(1.43*10^12 m)^2 = 15.57 W/m^2Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.