Sources A and B emit long-range radio waves of wavelength 450 m, with the phase

Question

Sources A and B emit long-range radio waves of wavelength 450 m, with the phase of the emission from A ahead of that from source B by 90°. The distance rA from A to a detector is greater than the corresponding distance rB from B by 87 m. What is the magnitude of the phase difference at the detector in rad?

I dont know what im doing wrong?
I take x/?=phase difference /360 degrees
so the corresponding phase difference= 360*87/450 = 69.6 degree
hence the phase difference at the detector= 90+69.6 =159.6 degree.

then converting to rad, 159.6 (pi/180 deg) = 2.7855 rad but wiley keeps saying that this answer is wrong? please help.

Explanation / Answer

Given that wave length of the waves is =450m intial phase difference is0.5 the path difference between the waves is 87 m so the phase difference is =2/(path difference)                                           =2/450(87)                                           =0.386 so the over all phase difference is 0.886 rad    

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