<p>alum tank volume = .03 m^3<br />filled to top with mercury<br />temp = 20 deg

Question

<p>alum tank volume = .03 m^3<br />filled to top with mercury<br />temp = 20 degrees C<br />tank placed into chamber w/a interior temp = 70 degrees C</p>
<p>coeff of vol. exp of mercury = 1.82 x 10^-4</p>
<p>coeff of linear exp of alum = 23 x 10^-6</p>
<p>after reaching thermal equalibrium of interior chamber, How much mercury spilled?</p>
<p>a. 1.69 x 10^-4 b. 6.60 x 10^-5 c. 2 x 10^-4 d. 1.92 x 10^-4 e. 2.52 x 10^ -5 (all in m^3).</p>
<p>I came up with 1.99 x 10^-4 but it is not one of the answers</p>

Explanation / Answer

Data: Volume, V = 0.03 m^3 Change of temperature, t = 70 - 20 = 50 deg C Co efficient of volume expansion of mercury:
Hg = 1.82 x 10^-4 /deg C Coefficient of linear expansion of aluminum:
Al = 23 x 10^-6 /C Solution: Coefficient of apparent expansion of mercury:
a = Hg - 3 Al = 1.82 x 10^-4 - 69 x 10^-6 = 1.13 x 10^-4 /C Volume ov mercury overflown, V = a V t                                        = 1.13 x 10^-4 * 0.03 * 50                                        = 1.69 x 10^-4 m^3 Ans: Option - a [ V = 1.69 x 10^-4 m^3 ]

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.