hi i took this problem to the tutoring center at occ and they guided me in the w

Question

hi i took this problem to the tutoring center at occ and they guided me in the wrong direction. i dont know why this one i am having so much trouble with.

if you could show me the steps to work it out and the final answer i would appreciate it!!

Three point charges are located at the corners of an equilateral triangle as in the figure below. Find the magnitude and direction of the net electric force on the 0.70 µC charge. (A = 0.70 µC, B = 6.60 µC, and C = -4.30 µC.)

answers-

1. MAGNITUDE: ? N

2. DIRECTION: ? degrees [counterclockwise from the +x-axis]

thank you!!

Explanation / Answer

Do you have unlimited tries? (got to go in a second, so this might have an error) electric force= kqq/r^2 from C: 9*10^9*0.7*10^-6*4.3*10^-6/.5^2=.1086N to the right from B: 9*10^9*6.6*10^-6*0.7*10^-6/.5^2=.16632N which we need to break up .16632*cos(60 degrees)=0.0836 in the X .16632*cos(30 degrees)=0.144 in the Y so it's sqrt(x^2+y^2)=actual sqrt((0.0836-.1086)^2+0.144^2)=.146 N angle is tangent inverse of the combination or arctan(0.144/(0.0836-.1086)=-80 degrees

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