The work function for platinum is 6.35 eV. (a) Convert the value of the work fun

Question

The work function for platinum is 6.35 eV. (a) Convert the value of the work function from
electron volts to joules. (b) Find the cutoff frequency for platinum. (c) What maximum wavelength of
light incident on platinum releases photoelectrons from the platinums surface? (d) If light of energy
8.50 eV is incident on zinc, what is the maximum kinetic energy of the ejected photo-electrons? Give
the answer in electron volts. (e) For photons of energy 8.50 eV, what stopping potential would be
required to arrest the current of photoelectrons?

Explanation / Answer

A) 6.35X 1.6x10^-19 = 3.81x10^-18 J B) E= hf f =E/h = 6.35/4.14X 10^-15 = 1.5338X10^15 Hz C) C= f lamda lamda= c/f = 3x10^8/ 1.53x10^15 = 1.96X10^-7m D) What is the work function for zinc ???? KE= hf- work function Stopping potential => E=qV V=E/q

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