A car starts from rest at point A and moves to point B in 25 second. Point B. is

Question

A car starts from rest at point A and moves to point B in 25 second. Point B. is 500 meters to the right of Point A. The car begins to slow down as it passes through point B until it finally comes to a complete stop at point C. Point C is 100 meter to the right of point B.

A) What is the acceleration of the car as it moves from Point A to point B?_____ M/S square
B) What is the velocity of the car when it reaches point B?___m/s
C) What is the accelerations of the car as it moves from point B to point C?_____m/s square
d) How long does it take for the car to move from point A to point C?______ seconds
e) What is the average velocity of the car for the entire trip from point A to point C?_____ M/S

Explanation / Answer

a) Acceleration from Point A to point B

s= ut+0.5at2

500 = 0 + 0.5a(25)2

a= 500/ (312.5)=1.6 m/s^2
b) Velocity at B:

V = 0 + 1.6(25)=40 m/s

c)From point B to point C, the body is undergoing retardation.

0^2 - 40^2 = 2(a)(100)

-1600/200= a

a= -8 m/s^2

d)time taken by car from Bto C

t = (0-40)/(-8) = 5 seconds

total time taken; 25 + 5 = 30 seconds

e)Avg velocity = total displacemnt /total time= 600 m/30 seconds=20 m/s

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