For each thin lens shown in the figure , calculate the location of the image of
ID: 2022608 • Letter: F
Question
For each thin lens shown in the figure , calculate the location of the image of an object that is 19.0 to the left of the lens. The lens material has a refractive index of 1.50, and the radii of curvature shown are only the magnitudes.
Please include the work and formulas used, so I can understand how it was done!
Thank you!
For each thin lens shown in the figure , calculate the location of the image of an object that is 19.0 to the left of the lens. The lens material has a refractive index of 1.50, and the radii of curvature shown are only the magnitudes. s^'(d) = Please include the work and formulas used, so I can understand how it was done! Thank you! s^'(c) = = =Explanation / Answer
if p is the object distance and q is the image distance then we get the relation as(1 / f) = (1 / p) + (1 / q)
(1 / q) = (1 / f) - (1 / p)
=(p - f) / f p
q = f p / (p - f) ............. (1)
as from the given
p = 19.0 cm
the thin lens equation is given by
(1 / f) = (n - 1) [(1 / R1) - (1/ R2)] ..........(2)
n = 1.5
(a)
here we are given
R1 = 10 cm
R2 = - 15 cm
substitute in (2) for f and then in (1) for the imagedistance q
q = ........ cm to the right of the lens
(b)
here we are given
R1 = 10 cm
R2 =
substitute in (2) for f and then in (1) for theimage distance q
q = ........ cm to the left of thelens
(c)
here we are given
R1 = - 10 cm
R2 = 15 cm
substitute in (2) for f and then in (1) for the imagedistance q
q = ........ cm to the left of thelens
(d)
here we are given
R1 = 10 cm
R2 = 15 cm
substitute in (2) for f and then in (1) for the imagedistance q
q = ........ cm to the left of thelens (1 / f) = (1 / p) + (1 / q) (1 / q) = (1 / f) - (1 / p) =(p - f) / f p q = f p / (p - f) ............. (1) as from the given p = 19.0 cm the thin lens equation is given by (1 / f) = (n - 1) [(1 / R1) - (1/ R2)] ..........(2) n = 1.5 (a) here we are given R1 = 10 cm
R2 = - 15 cm
substitute in (2) for f and then in (1) for the imagedistance q R2 = - 15 cm q = ........ cm to the right of the lens (b) here we are given R1 = 10 cm
R2 =
substitute in (2) for f and then in (1) for theimage distance q R2 = substitute in (2) for f and then in (1) for theimage distance q q = ........ cm to the left of thelens (c) here we are given R1 = - 10 cm
R2 = 15 cm
substitute in (2) for f and then in (1) for the imagedistance q R2 = 15 cm q = ........ cm to the left of thelens (d)
here we are given
R1 = 10 cm
R2 = 15 cm
substitute in (2) for f and then in (1) for the imagedistance q
q = ........ cm to the left of thelens here we are given R1 = 10 cm
R2 = 15 cm
substitute in (2) for f and then in (1) for the imagedistance q R2 = 15 cm q = ........ cm to the left of thelens
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