A 50.0-N box is sliding on a rough horizontal floor, and the only horizontal for
ID: 2022758 • Letter: A
Question
A 50.0-N box is sliding on a rough horizontal floor, and the only horizontal force acting on it is friction. You observe that at one instant the box is sliding to the right at 1.75 m/s and that it stops in 2.25 s with uniform acceleration. The force that friction exerts on this box is closest to: 8.93 N50.0 N
38.9 N
3.97 N
490 N
A 50.0-N box is sliding on a rough horizontal floor, and the only horizontal force acting on it is friction. You observe that at one instant the box is sliding to the right at 1.75 m/s and that it stops in 2.25 s with uniform acceleration. The force that friction exerts on this box is closest to:
8.93 N
50.0 N
38.9 N
3.97 N
490 N
Explanation / Answer
let the friction force be Fr, acceleration to be a, since final sppeed vf = 0,
init speed v0 = 1.75m/s, t = 2.25s , mass m = 50.0N/g , we have:
vf = 0 = v0 + at
a = -v0/t = -1.75m/s / 2.25s = -0.78m/s2
then,
Fr = ma = (50.0N/9.8m/s2) * (-0.78m/s2) = -3.98N
the magtitude of the friction force is 3.98N
answer it is closest to 3.97N i nthe list
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