Hello everyone! I am having a bit of trouble trying to understand this problem o

Question

Hello everyone! I am having a bit of trouble trying to understand this problem on capacitors. I know it should be easier than I am making it, I am just having a hard time understanding the layout of the diagram.

1b.Compare the electric potential (V) across C2 and C3.

i.|V2| is less than |V3|
ii.|V2| is equal to |V3|
iii.|V2| is greater than |V3|

1c.Compare the electric potential (V) across C1 and C5.
i.|V1| is less than |V5|
ii.|V1| is equal to |V5|
iii.|V1| is greater than |V5|

1d.  What is the equivalent Capacitance of the entire network?

Thank you for anyone who can help me get started with this problem!

Explanation / Answer

The first parallel circuit is C4 and C5 40 F+50 F=90 F, I will

call this C6. C2 and C3 are in parallel and in series with C6

20 F and 30 F=50 F with the series circuit:

(50E-6*90E-6)/(50E-6+90E-6)32.14 F in series with 10 F

(32.14E-6*10E-6)/(32.14E-6+10E-6)7.63 F=Ceq

q=C*V=7.63E-6*645.76 C total charge in system

45.76 C/10 F4.58 V drop across the 10 F capacitor

6 V-4.58 V=1.42 V for the remaining circuit

45.76 C/50 F0.915 V drop across C2 and C3

45.76 C/90 F0.508 V drop across C4 and C5

1a) C2 and C3 are in parallel

1b) C2 and C3 each have 0.915 V because they are in parallel (equal)

1c) V1 is greater than V5 look above

1d) Ceq=7.63 F look above for method of calculation

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.