Two circular holes, one larger than the other, are cut in the side of a large wa
ID: 2023958 • Letter: T
Question
Two circular holes, one larger than the other, are cut in the side of a large water tank whose top is open to the atmosphere. Hole 1 is the larger hole, and hole 2 is the smaller hole. The center of one of these holes is located 6.36 times as far beneath the surface of the water as the other. The volume flow rate of the water coming out of the holes is the same. (a) Decide which hole (1 or 2) is located nearest the surface of the water. (b) Calculate the ratio of the radius of the larger hole to the radius of the smaller hole, rA/rB.Explanation / Answer
(a)Larger hole is located the nearest the surface of the water
velocity at larger hole V L = [ 2 g h ]
velocity at smaller hole V s = [ 2 g * (6.36)h ] given rate of flow are equal So ,
According to continuity equation
AL * V L = A s * Vs where A L = rLL2 A s = r s2 using this data you find required answer (a)
Larger hole is located the nearest the surface of the water
velocity at larger hole V L = [ 2 g h ]
velocity at smaller hole V s = [ 2 g * (6.36)h ] given rate of flow are equal So ,
According to continuity equation
AL * V L = A s * Vs where A L = rLL2 A s = r s2 using this data you find required answer (a)
Larger hole is located the nearest the surface of the water
velocity at larger hole V L = [ 2 g h ]
velocity at smaller hole V s = [ 2 g * (6.36)h ] given rate of flow are equal So ,
According to continuity equation
AL * V L = A s * Vs where A L = rLL2 A s = r s2 using this data you find required answer (a)
Larger hole is located the nearest the surface of the water
velocity at larger hole V L = [ 2 g h ]
velocity at smaller hole V s = [ 2 g * (6.36)h ] given rate of flow are equal So ,
According to continuity equation
AL * V L = A s * Vs where A L = rLL2 A s = r s2 using this data you find required answer
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