A block is attached to an ideal spring. The spring is horizontal, and the block

Question

A block is attached to an ideal spring. The spring is horizontal, and the block is on a frictionless surface. The block is released from rest when the spring is stretched by a distance of A from its natural length, and the block then oscillates in one dimension with an angular frequency ?1. An identical block is then attached to an identical horizontal spring, with this block supported by the same frictionless surface. This second block is released from rest when the spring is stretched by a distance of 2A from its natural length, and this block then oscillates in one dimension with an angular frequency ?2.
(a) How do the two angular frequencies compare?
?2 = 0.5?1
?2 = ?1
?2 = (?1 multiplied by the square root of 2)
?2 = 2?1


(b) Briefly justify your answer to part (a). This part won't be graded, but we ask these kinds of questions on the tests so they're good practice.


(c) You make a simple pendulum by tying a long string to a ball. When you are here on the surface of the Earth, you measure the period of oscillation of the pendulum, for small-amplitude oscillations. You and your pendulum then journey to planet Zorg, and you measure the period of oscillation of your pendulum again, for small-amplitude oscillations at the surface of Zorg. You find that the oscillation period on Zorg is exactly two times longer than the period here on Earth. How does the value of the gravitational acceleration at Zorg's surface compare to that at the surface of the Earth?
gZorg = 0.25 gEarth
gZorg = 0.5 gEarth
gZorg = gEarth
gZorg = 2 gEarth
gZorg = 4 gEarth

Explanation / Answer

  

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.