A)Which is larger, the gravitation attraction between an electron and a proton s

Question

A)Which is larger, the gravitation attraction between an electron and a proton separated by a distance d or the
electric attraction between an electron and a proton separated by a distance d? Justify your answer by
forming a ratio of the sizes of the two forces.
B) Given the answer to part A), why is the gravitational force between the earth and a falling eraser greater than
the electric force between the earth and the falling eraser?
C) Compare the size of the gravitational force on an eraser resting on the floor with the electric force that the
floor exerts on the eraser.

Explanation / Answer

Given mass of electron me = 9.11*10-31kg mass of proton mp = 1.672*10-27kg mass of proton mp = 1.672*10-27kg Charge of electron and proton qp= qe =1.6*10-19kg Let r be the separation between them Gravitational force Fg= Gmpme/r2      = (6.67*10-11)(9.11*10-31kg)(1.672*10-27kg)/r2     = 101.59*10-69  /r2 Electric field force Fe=1/4q1q2/r2      = (9*109)(1.6*10-19kg)2/r2     = 23.04*10-29  /r2 Fe/Fg = 0.22*1040 Fe ˜1040Fg A) Electric field force is larger B) Because of large mass of the earth gravitationel force is larger C) Fg=GmEm/r2 Here mE is mass of the earth 5.97*1022kg keeping mass of the eraser is small       Fe = 1/4q1q2/r2 So Fg >> Fe        = (6.67*10-11)(9.11*10-31kg)(1.672*10-27kg)/r2     = 101.59*10-69  /r2 Electric field force Fe=1/4q1q2/r2      = (9*109)(1.6*10-19kg)2/r2     = 23.04*10-29  /r2 Fe/Fg = 0.22*1040 Fe ˜1040Fg A) Electric field force is larger B) Because of large mass of the earth gravitationel force is larger C) Fg=GmEm/r2 Here mE is mass of the earth 5.97*1022kg keeping mass of the eraser is small       Fe = 1/4q1q2/r2 So Fg >> Fe   Electric field force Fe=1/4q1q2/r2      = (9*109)(1.6*10-19kg)2/r2     = 23.04*10-29  /r2 Fe/Fg = 0.22*1040 Fe ˜1040Fg A) Electric field force is larger B) Because of large mass of the earth gravitationel force is larger C) Fg=GmEm/r2 Here mE is mass of the earth 5.97*1022kg keeping mass of the eraser is small       Fe = 1/4q1q2/r2 So Fg >> Fe   Electric field force Fe=1/4q1q2/r2      = (9*109)(1.6*10-19kg)2/r2     = 23.04*10-29  /r2 Fe/Fg = 0.22*1040 Fe ˜1040Fg A) Electric field force is larger B) Because of large mass of the earth gravitationel force is larger C) Fg=GmEm/r2 Here mE is mass of the earth 5.97*1022kg keeping mass of the eraser is small Here mE is mass of the earth 5.97*1022kg keeping mass of the eraser is small       Fe = 1/4q1q2/r2 So Fg >> Fe  

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