A gas initially at a temperature of 0 oC and a pressure of 148 kPa is compressed

Question

A gas initially at a temperature of 0 oC and a pressure of 148 kPa is compressed isothermally from 35 L to 16 L. What is the work required?

Answer in kj (kilo joules) and upto 1 decimal place. Give the absolute value without plus or minus sign.

This is what I did:

W = P (Vf - Vi)

Pressure in atm is 1.46, and I didn't change L to m^3. Answer I got was -28.5J but in Kj that's like 0.0285 and he asked for the answer in one decimal, making it 0.0, so I guess my answer is wrong. Please mind the units that I need my answer in.

Explanation / Answer

A gas initially at a temperature of 0 oC and a pressure of 148 kPa is compressed isothermally from 35 L to 16 L. What is the work required?

Answer in kj (kilo joules) and upto 1 decimal place. Give the absolute value without plus or minus sign.

Here we have to take pressure as 148*10^3 Pa(As we got kilo pascal)

Volume as (35*10^-3) and (16*10^-3)cubic meter(we need to convert liter into into cubic meter )

So W=P*(Vf-Vi)=148*10^3*19*10*-3
=148*10^3*10^-3*19
=2812 Joules
=2.8 Kj

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