The figure above is a long, massless stick with evenly spaced marks. The distanc

Question

The figure above is a long, massless stick with evenly spaced marks. The distance between two adjacent marks is 8.50 cm. In each of the following problems a pivot will be placed at a point on the stick. The pivot will hold that point fixed, but allow the stick to rotate. You will be finding conditions that will keep the stick in static equilibrium given different forces. All forces will be applied to the stick perpendicular to the length of the stick.

A pivot is placed at Point L and a force of 22.0 N is directed downward perpendicular to the stick at Point E. What is the magnitude and direction of the force which must be applied at point J in order to obtain static equilibrium?

A pivot is placed at Point G and a force of 11.0 N is directed downward perpendicular to the stick at Point E. What is the magnitude and direction of the force which must be applied at point F in order to obtain static equilibrium?

A pivot is placed at Point D and a force of 37.0 N is directed downward perpendicular to the stick at Point B. One at a time, each of the following 3 forces are applied to the stick in the manner described. Where must these forces be applied in order to achieve static equilibrium? If the is no point that will work within reason, select the option None.

               A force of 12.3 N directed downward perpendicular to the stick.
A B C D E F G H J K L None A force of 8.2 N directed upward perpendicular to the stick.
A B C D E F G H J K L None A force of 24.7 N directed upward perpendicular to the stick.

Explanation / Answer

(1) 22 * (E-L) = F * (J-L) 22 * 4 = F * 3 F = 29.3 down (2) 11 * (G-E) = (G-F) * F 11 * 8 = 6 * F F = 14.7 up (3) 37 * (B-D) = 12.3 (D-X) 37 * 2 = 12.3 (D-X) (D-X) = 6 X = K down (4) 37 * 2 = 8.2 (D-X) (D-X) = 9 X = Doesn't exist (None) (5) 37 * 2 = 24.7 (D-X) (D-X) = 3 X = H up

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