Here is my question: A 1kg mass undergoes a constant acceleration and when start
ID: 2026749 • Letter: H
Question
Here is my question: A 1kg mass undergoes a constant acceleration and when starting from rest travels 10m in 1 sec. Find the speed of the block at the end of it's first sec, the accerlation of the block, and the force necessary to produce this acceleration.
Now I know that my mass= 1 kg, Vo= Om, V= 10m, t= 1sec
And what I want is: a,speed, Force
The first formula use is to find acceleration right? which is V=Vo + at then you isolate the a to a= V-Vo/ t
which gives me a=10m/ 1 sec or 10m/sec
now i can find my force with F=m(a) which would be F=1kg(10m/sec)
This is where I get lost cause the answer supposed to be 20N. Can anybody help figure out where I might be going wrong or how to get the rest of the answers.
Explanation / Answer
initial velocity = 0
distance travelled = 10m
hence s= 1/2 at^2 gives 10= 1/2 *a(1)
hence acceleration = 20
speed of the block is obtained by using v=u+at
v= 20
force = mass* a=20 N
u took V=10 but its not gifen inthe question that V=10
u may say V=distance/time = 10 but since the body is accelerating u cannot use V= s/time
s=ut is valid only when the body is not acceleratin
general kinematic equatio is s= ut+ 1/2at^2
from this we can get any formula
like u did ,u took acceleration as zero and got s= ut and u=V=10 which is wrong
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