The figure below is a long stick with evenly spaced marks. The distance between

Question

The figure below is a long stick with evenly spaced marks. The distance between two adjacent marks is 5.50 cm.

Ihe figure helow is a long stick with evenly spaced marks. The distance hetween two adjacent marks is 5. cm. For each of the following foroes or set of foroos determine the requested torque, Usc Point F as the axis of rotation. Use the sign convention that a counterclockwisc (CCW) torque is considered positive and a clockwise (CW) torque is considered negative. A force of 35.0 N is directed upward perpendicular to the stick at Point C, What is the torque from this force? 5.78 N*m You are correct. r receipt no. is 157 7856 38 N m Submit Answer Incorrect. Iries 1/1 previous Iries A force of 39.0 N is directed upward perperdicular to the stick at Point K. What is the torgue from this force? Subrnit Answer Tries 0/10 A force of 40.0 N is directed upward at angle 35.6 to the right of the perpendicular to the stick at Point H. What is the torque from this forcer Submit Answer Tries 0/10 A farce of 29.0 N is applied horizontally to the left at H. What is the toque from this force? Submit Aner Tries 0/10 tarque from these two forces? Submit Answer Tries 0/10 Two forces are applied simultaneously to the stick. A force of 35.0 N is directed upward perpendicular to the stick at Point C and a force of 39.0 N is cirected upward perpenclicular to the stick at Point K. What is the net

Explanation / Answer

torque = r x F

F = 35 N  

r = 3(5.50) = 16.5 cm = 0.165 m

torque = 0.165 x 35 = 5.78 N m  
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F = - 29 j

r = +(2 x 0.055)i = 0.11 i

torque = r x F = - 3.19 N m k

Ans: - 3.91 N m  

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F = 39j

r = - 0.11 i

torque = r x F = - 3.91 N m

Ans: - 3.91

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F = 40 cos35.6i + 40sin35.6 j

r = 0.11 i

torque = r x f = (0.11 x 40 x sin35.6) k

= 2.56 N m

Ans: 2.56

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F = 29i

r = 0.11 i

torque =r x F = 0  

Ans: 0

---------------------

net torque = 5.78 + (-3.91)

= 1.87 N m

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