Experiment 5.5: Estimating the Osmolaritv of Plant Cells 0 M NaCl (DI water) 0.1

Question

Experiment 5.5: Estimating the Osmolaritv of Plant Cells 0 M NaCl (DI water) 0.1 M NaC 0.2 M NaCl 0.3 M NaCl 0.4 M NaCl 0.5 M NaCl 0.6 M NaCl Pre-weight (g) Post-weight (g) Gain or Lost Percent weight change (%) 2.74 3.58 +0.84 2.65 3.08 +0.43 16.23 2.64 2.50 0.14 5.30 2.42 1.89 0.53 -21.90 2.26 1.63 0.63 27.88 2.09 1.48 -0.61 29.19 1.93 1.93 -0.61 31.61 30.66 Data Analysis Submission 5.5 . Data Table (your data) Osmolarity of Potato 35.00 25.00 0 15.00 C 5.00 y =-107.21x + 22.307 Graph: Conc. vs. % weight change Trendline, R2 value, and equation of trendine 15.00 0.4 0.5 0.6 -15.00 -25.00 35.00 isosmotic point Concentration (M)

Explanation / Answer

Osmolarity of solution is the concentration of a solution expressed as the total number of solute particles per litre.

Osmolarity of plant cell is estimated by change in weight. Plant cells conserve their concentration level of water in the cell to be within the reasonable range in order to continue their regular metabolic activities.

In this experiment As shown in the table shows, the percentage change in weight is from 30.66 to -31.61

as NaCl concentration increased from 0.0M to 0.6M. The Osmotic concentrations were

grater than zero in sucrose solution of 0.0M, 0.1M meaning that these

cells were hypertonic. On the other hand, the osmotic concentrations were less than zero in sucrose solution from 0.2M and 0.6M signifying that, these cells were hypotonic.

Higher respiration at salinities well below the isomotic point reflect the 'work' being done in hyper- osmotic regulation

Here isomotic point is 0.21 M of NaCl

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