Answer in units of m/s 016 (part 1 of 6) 10.0 points Apartide of man 8.066 x 10

Question

Answer in units of m/s 016 (part 1 of 6) 10.0 points Apartide of man 8.066 x 10 as kg aud charge of magnitade 32 x 109 C is accelkr- 012 10.0 points 20 A has a length ated from rest in the plane of the page t A wire carrying a curent 0.1 m between the pole faces of a magnet at an angle 60 (see the figure). The magetie a potential difference of 163 V between to The particke is la Beld is approoxinaately uniform at 0.5 T Waraled plates as sbowa. The particle is lar jected throngh a hole in the right-band plate into a region of soce contaiming a uniform magmetie Beld of magnitade 0.42 T oriented perpendicular to the plane of the page. The ignore the ield beyoad the pole pieces. madden (tam3869)-HW Ch. 22-riy-(36790 particle cures in a emicireslar path and strikes a deteetor 020 (part S of6) 10.0 points What is the distance from the point of inje- tion to the deteetr? Magnetic Field B 021 (part 6 of 6) 10.0 points hole What is the work done by the magnetie field ou the charged particle during the semicireu lar trip? 1. W-336135 x 10-17 J 2x 10 What is the sign of the charge 1. The charge q cannot be determined 2. The charge q is negative (- 3. The charge q is positive of the parti 2. W cle? Neglect relativistic effects 4 W-264 x 10-1 5, W ..-136135 10 17 J . W-1056 x 10 7. W 528 x 1017 J 017 (part 2 of 6) 10.0 points Which way does the maguetic field point? 1. Cannot be determined 2. To the right 3. To the left 022 (part 1 of 2) 10.0 points Note thatA single charged positive lou has a charge equal to the elementary chargee Toward the bottom of page &. Into the page 6. Toward the top of page 7. Out of the page A single dharged positive n that hasa mass of 6.12 x 10kg moves clockwise with a speed of 1.01 x 10 m/s The positively charged ion s in a cicular path that has a radius o 5.72 Find the stoength of the uniform magaetic feld. Anewwe in its offT 018 (part 3 of 6) 10.0 points What is the speed of the charged particle as it enters the region of the magnetic eld 023 (part 2 of 2) 10.0 points Answer in units of m/s What is its directi 1. Noue of these 019 (part 4 of 6) 10.0 points What is the magnitude of the force exerted on the charged particle as it enters the region of the magnetic fiekd B? 3, to the oberver's eft Answer im units of N away froem the obeerv

Explanation / Answer

Question 16:

Charge q cannot be determined because magnetic filed direction is not mentioned

Question 17:

Field direction cannot be determined, because charge sign is not known.

Question 18:

velocity, v = sqrt [ 2qV/m ]

given:

q = 3.2*10-19 C

V = 163 V

m = 8.466*10-26 kg

v = sqrt [ 2*3.2*10-19*163 / 8.466*10-26 ]

v = 35103.03 m/s

Question 19:

F = qvB

q = 3.2*10-19 C

v = 35103.03 m/s

B = 0.42 T

magnitude of force, F = (3.2*10-19 C)*(35103.03 m/s)*(0.42 T)

magnitude of force, F = 4.72*10-15 N

Question 20:

radius, r = mv/qB

m = 8.466*10-26 kg

q = 3.2*10-19 C

v = 35103.03 m/s

B = 0.42 T

radius, r = mv/qB = 0.0221 m

distance betweeen the point of projection and the detector is the diameter.

d = 2r = 2*0.0221 = 0.0442 m

distance betweeen the point of projection and the detector is 4.42 cm

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