The figure shows a wire ring of radiusa-1.94 cm that is perpendicular same magni

Question

The figure shows a wire ring of radiusa-1.94 cm that is perpendicular same magnitude 8 magnitude of the force the field exerts on the ring if the ring carries a current-4.83 mA. to the general direction of a radially symmetric, diverging magnetic field. The magnetic field at the ring is everywhere of the 4.06 mT, and its direction at the ring everywhere makes an angle 8-13.5with a normal to the plane of the ring. The twisted lead wires have no effect on the problem. Find the the tolerance is +/-9%

Explanation / Answer

I = 4.83 mA, B = 4.06 mT, r = 1.94 cm, theta = 13.5 degrees;

since the field is acting on the entire circumference, therefore   

L = 2*pi*r

F = BILsin(theta);

= 4.06*10^(-3)*4.83*10^(-3)*2*pi*0.0194*sin(13.5)

= 5.5*10^(-7) N.

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