The figure shows a wire ring of radius a 1.85 cm that is perpendicular to the ge

Question

The figure shows a wire ring of radius a 1.85 cm that is perpendicular to the general direction of a radially symmetric, diverging magnetic field. The magnetic field at the ring is everywhere of the same magnitude B = 4.38 mT, and its direction at the ring everywhere makes an angle =49.1°with a normal to the plane of the ring. The twisted lead wires have no effect orn the problem. Find the magnitude of the force the field exerts on the ring if the ring carries a current i = 5.12 mA. t Number Units the tolerance is +/-2

Explanation / Answer

we know,

F = Bil sin (x)

where B = magnetic field = 4.38*10-3 T, l = 2*pi*r = 2*3.14*1.85*10-2 , x = 49.1 degree and i = 5.12*10-3 A

F = 196.93 * 10-8 N

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