The electrons in the beam of a television tube have an energy of 20 keV. The tub

Question

The electrons in the beam of a television tube have an energy of 20 keV. The tube is oriented so that the electrons move horizontally from north to south. The vertical component of the Earth's magnetic field at the location of the television has a magnitude of 57.0 and is pointing down. a) In which direction does the force on the electrons act (enter N for north, S for South, E for East, or W for West)? Neglect a possible horizontal component of the magnetic field. Submit Answer Tries 0/6 b) What is the magnitude of the acceleration due to the vertical component of the Earth's magnetic field of an electron in the beam? Submit Answer Tries O/6 c) If the inclination of the earth's magnetic field near the TV is 78deg, calculate the magnitude of the force on the electrons due to the horizontal component of the Earth's magnetic field Submit Answer Tries 0/6

Explanation / Answer

Part C)

magnetic force acting on electron, F = q*v*Bx*sin(theta) (here theta is the angle between Bx and v)

= q*v*Bx*sin(180) (since v and Bx are anti parallel)

= 0

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