(800) Problem 2: A shopper pushes a grocery cart for a distance 19 m at constant
ID: 2031867 • Letter: #
Question
(800) Problem 2: A shopper pushes a grocery cart for a distance 19 m at constant speed on level ground. against a 35 N frictional force. He pushes in a direction 24° below the horizontal 20% Part (a) What is the work done on the cart by friction, in joules? Grade Summary 090 100% Potential sin0 cotanasin acos0 atan0 acotansinh0 cosh0 tanhcotanh0 Submissions Attempts remaining: 7 (090 per attempt) detailed view cos tan() ?|( egrees Radians Submit Hint I give up! Hints: 2% deduction per hint. Hints remaining: Feedback: 2% deduction per feedback. 20% Part (b) What is the work done on the cart by the gravitational force, in joules? 20% Part (c) What is the work done on the cart by the shopper, in joules? 20% Part (d) Find the magnitude of the force. in newtons, that the shopper exerts on the cart. ? 20% Part (e) what is the total work done on the cart. În joules?Explanation / Answer
a) work done on cart by friction = F d = -35 * 19
= -665 J
b)work done by gravitational force = F d cos 90 = 35 * 19 * cos 90
= 0 J
c) Ws + Wf = 0
Ws = 665 J
d) F = Ws / d cos theta = 665 / (19 * cos 24)
magnitude of force = 38.3 N
e) Wnet = Wf + Ws= -665 + 665
total work done = 0
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