12. 0/4 points | Previous Answers SerPSE9 7 P.036 My Notes Ask Your Teacher In a
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12. 0/4 points | Previous Answers SerPSE9 7 P.036 My Notes Ask Your Teacher In an electron microscope, there is an electron gun that contains two charged metallic plates 2.50 cm apart. An electric force accelerates each electron in the beam from rest to 9.70% of the speed of light over this distance. (Ignore the effects of relativity in your calculations.) (a) Determine the kinetic energy of the electron as it leaves the electron gun. Electrons carry this energy to a phosphorescent viewing screen where the microscope's image is formed, making it glow. (b) For an electron passing between the plates in the electron gun, determine the magnitude of the constant electric force acting on the electron Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully.N (c) Determine the acceleration of the electron. m/s2 (d) Determine the time interval the electron spends between the plates. Submit Anser Save ProgressPractice Another VersionExplanation / Answer
(a) KE=1/2 mv^2=0.5 x 9.11E-31 x (0.097 * 3E8)^2 = 3.86E-17 Joules
(b) Work = change in Kinetic energy = Force x displacement ==> Force = KE/d = 3.86E-17 / 2.50 E-2 = 1.544E-15 N
(c) a = F/m= 1.6948x1015 m/s^2
(d) t=sqrt(2d/a) = 5.432x10-9 sec
Hope this helps. let me know if you need any help.
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