A 62-kg woman cheats on her diet and eats a 537-Calorie (537 kcal) jelly doughnu

Question

A 62-kg woman cheats on her diet and eats a 537-Calorie (537 kcal) jelly doughnut for breakfast.

PLEASE ANSWER PARTS A, B, AND C. Thank you so much in advance!

i safari File Edit View History Bookmarks Window Help 70% E Tue 2:46:03 PM a webassign.net If 8.10 kg of ice at-5.00°C is added to 12.0 kg of water at 15°C, compute the final temperature oC How much ice remains, if any? Need Help? Talk to a Tutor Submit Answer Save Progress 5. + ?9.09 points SerCP9 11·P006. My Notes+Ask Your Te A 62-kg woman cheats on her diet and eats a 537-Calorie (537 kcal) jelly doughnut for breakfast. (a) How many joules of energy are the equivalent of one jelly doughnut? (b) How many stairs must the woman climb to perform an amount of mechanical work equivalent to the food energy in one jelly doughnut? Assume the height of a single stair is 15 cm. stairs (c) If the human body is only 26% efficient in converting chemical energy to mechanical energy, how many stairs must the woman climb to work off her breakfast? stairs Need Help? Talk to a Tuter 6. + ?9.09 points SerCP9 11·P.016. My Notes Ask Your Te Lead pellets, each of mass 0.70 g, are heated to 200°C. How many pellets must be added to 460 g of water that is initially at 20.0°C to make the equilibrium 27

Explanation / Answer

Solution:-

(a) Since 1 cal = 4.184 J

537 kcal = 537,000 cal = 2.25 x 10^6 joules

(b)From the question, the height of 1 stair step is 0.15 m

E = mgh = 2.25 x 10^6 joules

m = 62 kg (weight of the woman)
g = 9.82 m/s²

So, h

h = 3.69 x 10^3 m

= 24600 stair steps


(c) if the body is only 26% efficient, then

E(mechanical) = 0.26 * 2.25 x 10^6 joules = 585000 joules

h = E(mechanical)/mg = 962.80 m

=>6413.6 stair steps

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