A 600 g steel block rotates on a steel table while attached to a 1.20 m -long ho

Question

A 600g steel block rotates on a steel table while attached to a 1.20m -long hollow tube. Compressed air fed through the tube and ejected from a nozzle on the back of the block exerts a thrust force of 4.81N perpendicular to the tube. The maximum tension the tube can withstand without breaking is 60.0N . Assume the coefficient of kinetic friction between steel block and steel table is 0.60.If the block starts from rest, how many revolutions does it make before the tube breaks?

A 600g steel block rotates on a steel table while attached to a 1.20m -long hollow tube. Compressed air fed through the tube and ejected from a nozzle on the back of the block exerts a thrust force of 4.81N perpendicular to the tube. The maximum tension the tube can withstand without breaking is 60.0N . Assume the coefficient of kinetic friction between steel block and steel table is 0.60.knight_Figure_07_55.jpgIf the block starts from rest, how many revolutions does it make before the tube breaks?

Explanation / Answer

Fbreak = 60 N = mv^2/r ? v = sqrt(60r/m) m/s = 180 m/s
a = F/m m/s^2 = 11.775 m/s^2
t = v/a = 15.2866242
s = at^2/2 = 1372.875167
theta = s/r = 1372.875167
revs = theta/(2pi) = 218.499

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