16.2.4 Observe and explain a. Build circuit A using a battery, wires, and identi
ID: 2032315 • Letter: 1
Question
16.2.4 Observe and explain a. Build circuit A using a battery, wires, and identical bulbs (see the figures above) and then notice the brightness of the bulb. Then build circuit B and notice the brightness of the bulbs. Explain the differences in your observations using the concept of V field (potential difference) or any of the analogies. b. Build circuit C and notice the brightness of the bulbs. Explain your observations using the concept of current and any analogies c. Build cicuit D and notice the brightness of the bulbs. Now build circuit E and notice the brightness of the bulbs. Explain the differences in your observations using the concepts of potential difference and current. d. Can you say that a battery is a source of constant current? Explain your answer.Explanation / Answer
Answer a...in circuit B two bulbs 1 and 2 are connected in series therefore the total voltage is divided by two bulbs. Since bulbs are identical thew will glow of equal brightness but their intensity of brightness will be of less then that of bulb in A..this us due to the fact that equivalent resistence of the circuit A will be less.
Ans b... The brightness of circuit B and C will be same since both the bulbs are identical(same resistance) and same curent is flowing to it the potential drop by both the bulbs will be same.
Ans c.... Here(D) both the bulbs will glow equal brightness. But the brightness will be more as compared to circuit A ,B and C. Since they are in parallel equivalent resistance will be less.
In circuit E the bulb 1 will be brighter then 2 and 3. Since 1 is parallel to both 2 and 3 and 2 and 3 are in series.
Ans d... Here battery is ideal so it acts like a constant current source. But in reality it does not happen so.
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