Find the current in the circuit. The lightbulb in the circuit shown in the figur

Question

Find the current in the circuit. The lightbulb in the circuit shown in the figure(Figure 1) has a resistance of 13 ? and consumes 8.0 W of power; the rod is 1.17 m long and moves to the left with a constant speed. The strength of the magnetic field is 1.5 T. You may want to review (Pages 819-821) Express your answer using two significant figures Submit Request Answer Part Figure 1 of 1 Find the speed of the rod Express your answer using two significant figures u= m/s magnetic Submit Request Answer

Explanation / Answer

Part A

P = I2*R

I2 = P/R = 8/13 = 0.6154

I = 0.78446 amps (I = 0.78 amps in two sig figures)

Part B

e = I*R

e = 0.78446*13 = 10.198 volts

also,

e = B*dA/dt

e = B*L*v

v = e/BL

v = 10.198 / 1.5*1.17

v = 5.8108 m/s ( v = 5.8 m/s in two sig figures)

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.