A 900-kg roller coaster car isially at the top of a rise, at point . It then mov

Question

A 900-kg roller coaster car isially at the top of a rise, at point . It then moves 155 ft, at an angle of 40.0° below the horizontal, to a lower point B. (a) Choose the car at point B to be the zero configuration for gravitational potential energy of the roller coaster-Earth system. Find the potential energy of the system when the car is at points and B, and the change in potential energy as the coaster moves between these points at point at point change in potential energy (b) Repeat part (a), setting the zero configuration with the car at point at point at point B change in potential energy Need Help? Read it Submit Answer Save Progress Practice Another Version

Explanation / Answer

(a) As L = 155 feet = 47.24 meter

The vertical height of a from b (h) = L x sin40* = 47.24 x 0.64 = 30.37m

PE at a = mgh = 900 x 9.8 x 30.37 = 267821.83 J

PE at b = 0

=>delta PE = PE(final) - PE(initial) = -267821.83 J

(b) PE at a = 0

PE at b = -267821.83 J

=>delta PE = PE(final) - PE(initial) = -267821.83 J

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