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Question

n 12 of 12 Incorrect .. | Incorrect lrorrect- Incorect · Incorrect . horect enstax College Physics presented by Sapling Leaming An object 1.60 cm high is held 3.00 cm from a person's cornea, and its reflected image is measured 0.167 cm high. What is the magnification? Number 104 Where is the image? Number -31 cm Find the magnitude of the radius of curvature of the convex mirror formed by the cornea Number -5.72 em Note: this technique is used by optometrists to measure the curvature of the cornea for contact lens fitting The instrument used is called keratometer. or curve measurer Dl

Explanation / Answer

object distance =u=-3 cm

object height=ho=1.6 cm

image height=hi=0.167 cm

then magnification=-image height/object height

=-0.1044

let image distance be v.

as magnification=image distance /object distance

==>-0.1044=v/(-3)

==>v=0.313 cm

let focal length be f.

using mirror formula:

(1/v)+(1/u)=1/f

==>(1/0.313)-(1/3)=1/f

==>f=0.35 cm

then radius of curvature =2*f=0.7 cm

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