?https://edugen.wileyplus.com/eM ? | ? ? ? Halliday, Fundamentals of Physics, 10

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?https://edugen.wileyplus.com/eM ? | ? ? ? Halliday, Fundamentals of Physics, 10e | PRINTER VERSION | | BACK NEXT Chapter 09, Problem 050 A 4.90 g bullet moving at 733 m/s strikes a 550 g wooden block at rest on a frictionless surface. The bullet emerges, traveling in the same direction with its speed reduced to 462 m/s. (a) What is the resulting speed of the block? (b) What is the speed of the bullet-block center of mass? (a) Number Units (b) Number Units Click if you would like to Show Work for this question: Open Show Work Question Attempts: Unlimited SAVE FOR LATER SUBMIT ANSWER om/edugen/shared assignment testaglist.uni?id: asnmt213931 8#t 8:44 PM R4/4/2018

Explanation / Answer

Here ,

a) let the speed of the block is v

Using conservation of motion

0.00490 * (733 - 462) = 0.550 * v

v = 2.414 m/s

the speed of the block is 2.414 m/s

b) as the speed of center of mass will not change

speed of center of mass = 4.9 * 733/(4.9 + 550)

speed of center of mass = 6.47 m/s

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