An eight turn coil encloses an elliptical area having a major axis of 40.0 cm an

Question

An eight turn coil encloses an elliptical area having a major axis of 40.0 cm and a minor axis of 30.0 cm. The coil lies in the plane of the screen and has a 6.00 A current flowing clockwise around it. If the coil is in a uniform magnetic field of 2.07 x 10-4T directed toward the left of the screen, what is the magnitude of the torque on the coil? (Hint: The area of an elipse 's A·Tab. where a and b are, respectively, the semimajor and semiminor axes of the ellipse.) N -m 40.0 cm Need Help? |Read lt:11 Taktoa Tutor Show My Work (Optional) Submit Answer Save Progress Practice Another Version

Explanation / Answer

Given,

N = 8

B = 2.07 x 10-4T

I = 6 amps
A = ? a b = ? (0.200 m) (0.150m) = 0.094 m2

as from the given we can see that the field isparallel to the plane of the loop we get
   ? = 90°

? = N I A B sin? = (8) (6 amps) (0.094) (2.07 x 10-4T)sin90° = 9.34 x 10-4 N.m

the torque is directed to make the left hand side ofthe loop move toward you and the right hand side move away

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.