Alternative Exercise 31.83 9 of 10 Constants Part A An L-R-C series circuit has

Question

Alternative Exercise 31.83 9 of 10 Constants Part A An L-R-C series circuit has R-285 ? . At the frequency of the source, the inductor has reactance XL-905 ? and the capacitor has reactance XC-490 ? . The amplitude of the voltage across the inductor is 475 V What is the amplitude of the voltage across the resistor? Express your answer with the appropriate units. VRValue Units Submit Re Answer Part B What is the amplitude of the voltage across the capacitor? Express your answer with the appropriate units. Ve= Value Units Submit st Answer Part C What is the voltage amplitude of the source? Express your answer with the appropriate units. v.Valu Units Submit Part D What is the rate at which the source is delivering electrical energy to the circuit? Express your answer with the appropriate units. P," = Value Units Submit t Ans

Explanation / Answer

inductive reactance XL = 905

capacitive reactance Xc = 490

amplitude of voltage across inductor VL = Imax*XL

Imax = VL/XL = 475/905 = 0.525 A

part(A)

amplitude of voltage across resistor VR = Imax*R = 0.525*285 = 150 V

part(B)

amplitude of voltage across capacitor Vc = Imax*Xc = 0.525*490 = 257.25 V

part(C)

voltage amplitude of source Vmax = sqrt(VR^2 + (VL - Vc)^2)

Vmax = sqrt( 150^2 + (475 - 257.25)^2 ) = 264.4 V

part( D )

average power = (Imax^2*R)/2 = (0.525^2*285)/2 = 39.3 W

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