ssignment Submission For this assignment, you submit answers by question parts.

Question

ssignment Submission For this assignment, you submit answers by question parts. The number of submissions remaining for each question part only changes if you submit or change the answer ssignment Scoring Your last submission is used for your score. 1.-1 points SerCP10 23.P014 My Notes A concave mirror has a focal length of 70.5 cm (a) What is its radius of curvature? (b) Locate the image when the object distance is 100 ??. (Indicate the side of the mirror with the sign of your answer.) Describe the properties of the image when the object distance is 100 cm. (Select all that apply real o virtual O upright inverted (c) Locate the image when the object distance is 10.0 cm. (Indicate the side of the mirror with the sign of your answer.) cm Describe the properties of the image when the object distance is 10.0 cm. (Select all that apply.) real m virtual O upright inverted

Explanation / Answer

(a) radius of curvature = 2*focal length
= 2*70.5 = 141 cm
(b) Object distance (do) = -100 cm
focal length (f) = -70.5 cm
by mirror formula
(1/d0)+ (1/di) = 1/f
-(1/100)+(1/di) = -(1/70.5)
di = -238.983 cm
-ve sign indicate that it will be on the left side of the mirror or on the same side of that object.
Image will be real and inverted.
(c) When object distance is (do) = -10 cm
1/d0)+ (1/di) = 1/f
-(1/10)+(1/di) = -(1/70.5)
di = 11.653 cm
+ve sign indicate that the image will be on right hand side of the mirror or
opposite side than that of object.
Hence the image will be virtual and Upright.

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