IP Each of the 10 turns of wire in a vertical, rectangular loop carries a curren

Question

IP Each of the 10 turns of wire in a vertical, rectangular loop carries a current of 0.27 A. The loop has a height of 8.0 cm and a width of 15 cm. A horizontal magnetic field of magnitude 4.8×10?2 T is oriented at an angle of ?=65? relative to the normal to the plane of the loop, as indicated in the figure(Figure 1)

PrediotiCaloulate Problem 22 42 8of 11 -Part A IP Each of the 10 turns of wiro in a vertical ractangiar loop carnies a curent of 0.27 A Find the magntude of the magnetic force on each side of the loop. The loop has a height of 8.0em and a wiath af 15 cm A horizontall magnado fiold of magntude 48x10Tis criented at an anglo ct ralativo to the normal o he plane of the lcap, aa ind catod in the iguroF guro 1 Express your anewars using two significant figures soparated by commas Part B Find tho net magnotie force on the loop Express your anewwer using two significant figures. Submit Part Find the magnetic torque on the lccp. Express your answer using two significant figurnes Submit Figure -Part D 1 or 1 ?the loop can roste abonc avencal ais with only small amount of tricion, wE it end up with an onentaton grven by 9 = 4 ?=9f.ore=1MP? 80 cm Normal to loop

Explanation / Answer

F = NBIL sin theta

a) F top= 10*0.048*0.27*0.15*sin(90-65) = 0.0082 N k

F bottom = - Ftop = -0.0082 N k

F left = -10*0.048*0.27*0.08*sin90° = 0.010 N j

F right = -F left = -0.010 N j

b) Since top cancels out the bottom, and left cancels out the right, there is zero net force.

c) T = BLAN sin65° = 10*0.048*0.27*0.08*0.15*sin65° = 0.0014 Nm

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