A solenoid used to produce magnetic fields for research purposes is 2.3 m long,

Question

A solenoid used to produce magnetic fields for research purposes is 2.3 m long, with an inner radius of 25 cm and 1300 turns of wire. When running, the solenoid produced a field of 1.0 T in the center.

Part A

Given this, how large a current does it carry?

Express your answer using two significant figures.

A solenoid used to produce magnetic fields for research purposes is 2.3 m long, with an inner radius of 25 cm and 1300 turns of wire. When running, the solenoid produced a field of 1.0 T in the center.

Part A

Given this, how large a current does it carry?

Express your answer using two significant figures.

Explanation / Answer

Magnetic field inside solenoid is given by:

B = u0*n*i

n = N/L

B = u0*N*i/L

i = B*L/(u0*N)

Using given values:

N = 1300 turns

L = length of solenoid = 2.3 m

B = magnetic field = 1.0 T

i = 1*2.3/(1300*4*pi*10^-7)

i = 1407.91 Amp

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