The passenger side headlight on a truck hits the rear passenger door of a car. A

Question

The passenger side headlight on a truck hits the rear passenger door of a car. Assuming no friction from the road, (it is pure ice! that's why the truck hit the car!) where is momentum conserved?

Consider two rigid bodies, sphere A and sphere B. They collide such that the points of impact during the collision are points A and B on their respective surfaces. The velocities of these points, A and B, can be related by which of these equations?

A 500 kg block of wood is suspended from the ceiling by a 0.5 m cord for a ballistics test apparatus to measure the velocity of bullets. If a 0.035 kg bullet causes the 500 kg block of wood in which the bullet becomes embedded to swing 30 degrees from its initial position, what is the velocity of the bullet just as it strikes the wood block?

Momentum is conserved for the system of the 2 rigid bodies (the truck and the car) in the direction that is tangent to the surfaces of impact and also parallel to the road.

Explanation / Answer

using

h = L ( 1 + cos30 )

h = 0.5 X ( 1 + cos30 )

h = 0.933 m

v = ( 2 g h )1/2

v = ( 2 X 9.8 X 0.933 )1/2

v = 4.276 m/s

mA VA + mB VB = ( mA + mB ) v

0.035 VA = ( 0.035 + 500 ) X 4.276

VA = 61089.99 m/s  

the velocity of the bullet just as it strikes the wood block is VA = 61089.99 m/s  

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