THE ANSWER IS WRONG. THEY DID NOT CONVERT THE UNITS TO METERS. PLEASE EXPLAIN IN
ID: 2038048 • Letter: T
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THE ANSWER IS WRONG. THEY DID NOT CONVERT THE UNITS TO METERS. PLEASE EXPLAIN IN GREAT DETAIL.
In an experiment designed to measure the speed of light, a laser is aimed at a mirror that is 51.0 km due north. A detector is placed 105 m due east of the laser. The mirror is to be aligned so that light from the laser refelects into the detector. (a) When properly aligned, what angle should the normal to the surface of the mirror make with due south (b) Suppose the mirror is misaligned, so that the actual angle between the normal to the surface and due south is too large by 0.0050°. By how many meters (due east) will the reflected ray miss the detector? Mirror Laser Detector (a) Number 32 Units(degrees) umber 20.37 Units m Show transcribed image textExplanation / Answer
let ? be the angle between the incident and refllected rays
tan ? = 105/51000
=> ? = arctan(105/51000) = 0.118°
since incident angle = reflected angle and
incident angle + reflected angle = ?
the asked angle = angle of incidence ,? = ?/2 = 0.059°
b) now incident angle, ? = 0.059 + 0.0050 = 0.064°
therefore ? = 2*? = 0.128°
let the new detector position be x meter due east from source
tan ? = x/51000 = 2.23*10-3
=> x = 113.90 m
therefore shift in detector positon = x - 105 = 8.90 m away from source due east
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