eBook 5 09.09 points Previous Arswers A four-particle system is shown in the fig

Question

eBook 5 09.09 points Previous Arswers A four-particle system is shown in the figure below, and the masses of the perticles are m-3.2 kg m2 = 3.7 kg m3 3.2 kg m4 3.7 kg 20m (a) Find the moment of inertia I, about the x axis, which passes through m2 and ma (b) Find the moment of inertia ly about the y axis, which passes through my and m2 kg m2 The moment of Inertia of a system of particles with respect to a given axis is the sum of the products of the mass of esc Sutemit Answer Save Progress Practice Another Version 9.09 points OType here to search

Explanation / Answer

a)

m1 = 3.2 kg

r1 = distance of m1 from X-axis = 2 m

m4 = 3.7 kg

r4 = distance of m4 from X-axis = 2 m

Moment of inertia about X-axis is given as

Ix = m1 r12 + m4 r42

Ix = (3.2) (2)2 + (3.7) (2)2

Ix = 27.6 kgm2

b)

m3 = 3.2 kg

r3 = distance of m1 from X-axis = 2 m

m4 = 3.7 kg

r4 = distance of m4 from X-axis = 2 m

Moment of inertia about X-axis is given as

Iy = m3 r32 + m4 r42

Iy = (3.2) (2)2 + (3.7) (2)2

Iy = 27.6 kgm2

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