What is the equivalent resistance of the resistors inside the dashed box? What i

Question

What is the equivalent resistance of the resistors inside the dashed box? What is l1? What is 12? What is /? What is the power supplied by the battery? What is the power dissipated by the 5-2resistor? 262 12 18 V What is the current through the 4 ? resistor?- _____ [1 point] what is the current through the 5 ? resistor 11 point! What is the current through the 6 ? resistor?- A [1 point] [Circle the direction of the ( left / right ) [1/3 point ( left / right ) [13 poin ( left / right ) [13 poin 12 ?

Explanation / Answer

Remember:
For series combination
Req = R1 + R2 + R3 +...............
for parallel combination
1/Req = 1/R1 + 1/R2 + 1/R3 + ............
for 2 resistors in parallel it will be
Req = R1*R2/(R1+R2)
Using this Information:

In dashed box, 2, 1 and R are in series, So

Rs1 = 2 + 1 + 2 = 5 ohm

Nw Rs1, 3, and 4 ohm arein parallel, So

1/Rp = 1/5 + 1/3 + 1/4 = 47/60

Rp = 1.28 ohm (Part A answer)

Now 5 ohm out of dashed box and Rp are in parallel, So

1/Req = 1/5 + 1/1.28

Req = 5*1.28/(5 + 1.28) = 1.02 ohm

Now using ohm's law:

V = i*R

ieq = V/Req = 6/1.02 = 5.88 Amp

i1 = ieq = 5.88 Amp (Part B Ans)

Now remember in resistors parallel combination voltage distribution in each part will be same and in series combination current distribution in each resistor will be same.

Voltage in 5 ohm = Voltage in dashed box = E = 6 V

i2 = V2/R2

V2 = Voltage in 5 ohm = 6 V

i2 = 6/5 = 1.2 Amp (Part C answer)

i3 = i1 - i2 = 5.88 - 1.2 = 4.68 Amp (Part D answer)

Power is given by:

P = V^2/Req = 6^2/1.02 = 35.29 W (Part E answer)

In 5-ohm power will be

P = V^2/R = 6^2/5 = 7.2 W

Please upvote.

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.