11. An experiment is performed using a concave mirror of focal length f. For a w

Q: 11. An experiment is performed using a concave mirror of focal length f. For a w

11) option F is the correct answer. 12) B) vA > vB and nA angle of refraction means the the second material has more refractive index than first material. so, vA > vB 13) E) 0.87 Em we know, I is proportional to E^2 Intensity through polarizer, Ip = I*cos^2(30) Ip = I*0.75 Ip/I = 0.75 (E/Em)^2 = 0.75 E/Em = sqrt(0.75) E = Em*sqrt(0.75) E = 0.87*Em

ID: 2039992 • Letter: 1

Question

11. An experiment is performed using a concave mirror of focal length f. For a wide range ot iseis ject from the mirror, the corresponding distances g from the mirror to the screen on which theI formed are measured. If a graph of q vs. p is constructed, the result is: A. A straight line with a slope f. C. A straight line with a vertical interceptf. E. A curve that asymptotically approaches B. A straight line with vertical intercept ¡ D. A straight line with slope-1. F. A curve that asymptotically approaches (but never intersects) the axes (see below), nonzero values of p and q (see below). -t 12. A beam of light propagating in medium A with index of refraction nA passes across an interface into medium B with index of refraction ng. The angle of incidence is greater than the angle of refraction; vA and vB denote the speed of light in medium A and medium B. Which of the following is true? D. UA UB and nA nB 13. A linearly polarized electromagnetic wave is sent through a sheet of polarizing material oriented so that its transmission axis makes an angle of 30 with the incident electric field of the wave. The incident beam has an electric field of peak magnitude Em and average intensity I. What is the peak value of the electric field amplitude after it goes through the polarizing sheet? Side View 0° incident transmitted beam beam A. 0.30 Em D. 0.75 Em B. 0.50 Em E. 0.87 Em C. 0.60 Em

Explanation / Answer

11) option F is the correct answer.

12) B) vA > vB and nA < nB

angle of incidence > angle of refraction means

the the second material has more refractive index than first material.

so, vA > vB

13) E) 0.87 Em

we know,

I is proportional to E^2

Intensity through polarizer,

Ip = I*cos^2(30)

Ip = I*0.75

Ip/I = 0.75

(E/Em)^2 = 0.75

E/Em = sqrt(0.75)

E = Em*sqrt(0.75)

E = 0.87*Em

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11. An experiment is performed using a concave mirror of focal length f. For a w

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