018 11 59 PM 364/1004/12/2018 09-21 PM PrintCalculator of 11 Map apling Learning

Question

018 11 59 PM 364/1004/12/2018 09-21 PM PrintCalculator of 11 Map apling Learning Most of the motion generated by joints in the class lever is the forearm, the force human body are examples of levers. An example of a third which generates the motion is located in between the pivot point and the resistance force. The elbow acts as the pivot point, the biceps muscle pulls up on the forearm to move the mass which is held in the hand. Imagine you are holding an object in your hand with your forearm horizontal and your upper arm vertical so your elbow creates a 90 angle. If your biceps attach to your vertical while a 2.76 kg mass is held forearm 0.0468 m from the elbow and make an angle of 26.0 with the in your hand 30.32 cm from the elbow, what force is exerted by the biceps muscle? Ignore the mass of the up 16

Explanation / Answer

Using torque balance about the elbow:

Net Torque = 0

Torque = r*F

Clockwise Torque = CounterClockwise Torque

Weight held*distance from elbow = Force of muscle*distance of muscle from elbow

2.76*9.81*30.32*10^-2 = 0.0468*F*cos 26 deg

F = (2.76*9.81*30.32*10^-2)/(0.0468*cos 26 deg)

F = 195.16 N

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