The length of a closed organ pipe is 10.0 cm. The temperature is 25.0° C. (a) Wh

Question

The length of a closed organ pipe is 10.0 cm. The temperature is 25.0° C. (a) What is the speed of sound at this temperature? (b) What is the fundamental frequency? (c) Calculate the first overtone frequency. Hint: Don't go for shortcuts. Make sure to show how you get your answer, including pictures. Which harmonic is this? (d) Calculate the second overtone frequency. Hint: Don't go for shortcuts. Make sure to show how you get your answer, including pictures. Which harmonic is this? (f) Following the pattern, what is the frequency of the third overtone?

Explanation / Answer

(a)

speed of sound at 25 degree

v =331+0.6 ( 25)

= 346 m/s

(b) f= v/ 4L = 346/ 4(0.1 m) = 865 m/s

(c)

first overtone is equal to third harmonic

f3 = 3f = 3( 865) = 2595 Hz

(d)second overtone is equal to fifth harmonic

f5 = 5f = 5 ( 865) = 4325 Hz

(f)

third overtone is seventh harmonic

f7= 7f = 7 ( 865) = 6055 Hz

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.